If the ratio of maximum and minimum intensiti | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The ratio of maximum intensity to minimum intensity is given by the formula: $\frac{I_{\max}}{I_{\min}} = \left(\frac{a_1 + a_2}{a_1 - a_2}\right)

Vedclass · Accepted Answer

$7 : 5$

Vedclass · Answer

(D) The ratio of maximum intensity to minimum intensity is given by the formula: $\frac{I_{\max}}{I_{\min}} = \left(\frac{a_1 + a_2}{a_1 - a_2}\right)^2 = \frac{36}{1}$.Taking the square root on both sides,we get: $\frac{a_1 + a_2}{a_1 - a_2} = \frac{6}{1}$.Applying the componendo and dividendo rule: $\frac{(a_1 + a_2) + (a_1 - a_2)}{(a_1 + a_2) - (a_1 - a_2)} = \frac{6 + 1}{6 - 1}$.This simplifies to: $\frac{2a_1}{2a_2} = \frac{7}{5}$.Therefore,the ratio of the amplitudes is $\frac{a_1}{a_2} = 7 : 5$.

If the ratio of maximum and minimum intensities is $36 : 1$ in an interference pattern,then the ratio of amplitudes of the interfering waves is

Similar Questions

$n$ identical waves each of intensity $I_0$ interfere with each other. The ratio of maximum intensities if the interference is $(i)$ coherent and $(ii)$ incoherent is:

What is interference?

Interference cannot be observed in two sodium lamps of equal power because the two waves do not have a .....

$n$ incoherent sources, each emitting beams of intensity $I_0$, are superimposed at a point. The resultant intensity at the point is:

Two light waves of intensities $I_1$ and $I_2$ having the same frequency pass through the same medium at a time in the same direction and interfere. The sum of the minimum and maximum intensities is

Vedclass Test Series

Exam Paper Generator

Online Exam Module